Move analyze_excel.py, excel_to_markdown.py, and locator_helper.py into the tools/ subdirectory to improve project organization.
172 lines
5.3 KiB
Python
172 lines
5.3 KiB
Python
"""
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元素定位辅助工具 - 用于快速验证定位是否有效
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"""
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from playwright.sync_api import Page, Frame, Locator
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def debug_locator(frame: Frame, locator: Locator, timeout: int = 5000):
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"""
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调试定位器 - 检查定位是否有效并显示详细信息
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参数:
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frame: 页面或iframe对象
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locator: 定位器对象
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timeout: 超时时间(毫秒)
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返回:
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bool: 定位是否成功
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"""
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print(f"\n验证定位: {locator}")
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print("=" * 50)
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try:
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# 检查数量
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count = locator.count()
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print(f"元素数量: {count}")
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if count == 0:
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print("✗ 未找到任何匹配元素")
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return False
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# 检查第一个元素是否可见
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first_visible = locator.first.is_visible(timeout=timeout)
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print(f"第一个元素可见: {first_visible}")
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# 获取文本内容
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for i in range(min(3, count)): # 最多显示3个
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element = locator.nth(i)
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try:
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if element.is_visible(timeout=1000):
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text = element.inner_text(timeout=1000)
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print(f" 元素{i + 1}文本: {text[:100] if len(text) > 100 else text}")
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else:
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print(f" 元素{i + 1}: 存在但不可见")
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except:
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print(f" 元素{i + 1}: 无法获取信息")
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print("=" * 50)
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return True
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except Exception as e:
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print(f"✗ 验证失败: {e}")
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print("=" * 50)
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return False
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def try_multiple_locators(frame: Frame, selectors: list[str], timeout: int = 5000) -> Locator:
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"""
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尝试多个选择器,返回第一个有效的定位器
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参数:
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frame: 页面或iframe对象
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selectors: 选择器列表
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timeout: 超时时间(毫秒)
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返回:
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第一个有效的 Locator,如果没有则返回 None
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"""
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print(f"\n尝试 {len(selectors)} 个定位方式...")
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print("-" * 50)
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for i, selector in enumerate(selectors):
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print(f"[{i + 1}] 尝试: {selector}")
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try:
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locator = frame.locator(selector)
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count = locator.count()
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visible_count = sum(1 for j in range(count) if locator.nth(j).is_visible(timeout=1000))
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print(f" 找到 {count} 个元素,其中 {visible_count} 个可见")
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if visible_count > 0:
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print(f" ✓ 使用此定位器")
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print("-" * 50)
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return locator
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except Exception as e:
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print(f" ✗ 失败: {e}")
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print("-" * 50)
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return None
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def interactive_locate(frame: Frame):
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"""
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交互式定位调试 - 进入交互模式测试定位表达式
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"""
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print("\n进入交互式定位调试模式")
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print("输入定位表达式,输入 'q' 或 'quit' 退出")
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print("-" * 50)
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while True:
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try:
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selector = input("\n>>> ")
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selector = selector.strip()
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if selector.lower() in ('q', 'quit'):
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break
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if not selector:
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continue
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debug_locator(frame, frame.locator(selector))
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except KeyboardInterrupt:
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break
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except Exception as e:
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print(f"错误: {e}")
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print("退出调试模式")
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# 示例使用代码(单独运行此文件时的演示)
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if __name__ == "__main__":
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from playwright.sync_api import sync_playwright
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import re
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with sync_playwright() as pw:
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browser = pw.chromium.launch(headless=False)
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context = browser.new_context(ignore_https_errors=True)
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page = context.new_page()
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# 登录
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page.goto("https://68.11.34.30:8082/yonbip/resources/uap/rbac/login/main/index.html")
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main_frame = page.locator("#forwardFrame").content_frame
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main_frame.get_by_role("textbox", name="用户名").fill("BLDpengqiangqiang")
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main_frame.get_by_role("textbox", name="密码").fill("Cqbld123456.")
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main_frame.get_by_role("button", name="登录").click()
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confirm_btn = main_frame.get_by_role("button", name="确定")
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if confirm_btn.count() > 0:
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confirm_btn.click()
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# 循环切换 Inspector 和交互式调试
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print("\n" + "=" * 60)
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print("元素定位调试工具")
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print("=" * 60)
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print("循环模式:")
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print(" 1. Inspector 窗口 - 使用浏览器录制/选择元素")
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print(" 2. 交互式调试 - 验证定位表达式")
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print(" 输入 'q' 或 'quit' 退出程序\n")
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while True:
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# 1. 打开 Inspector 窗口
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print("\n【打开 Inspector 窗口】")
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print("请在 Inspector 中获取元素定位器,然后关闭 Inspector 继续...")
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page.pause()
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# 2. 进入交互式定位调试
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print("\n【进入交互式定位调试】")
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interactive_locate(main_frame)
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# 询问是否继续
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choice = input("\n是否继续下一轮调试?(y/n/q): ").strip().lower()
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if choice in ('n', 'q', 'quit'):
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print("退出程序")
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break
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elif choice in ('y', ''): # 默认继续
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continue
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else:
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print("未知选项,退出程序")
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break
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context.close()
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browser.close()
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