feat: support multiple managers in DiscreteMaterialPlanCleaner

- Add get_materials_to_delete_by_managers() function in db/materials_to_delete.py
  - Supports querying by single manager, multiple managers, or all managers
  - Uses IN clause for multi-manager queries
- Refactor DiscreteMaterialPlanCleaner to accept manager_names parameter
  - Accepts str, List[str], or None (for all managers)
  - Automatically normalizes parameter types in __init__
  - Updates preload_data() with appropriate log messages

Co-Authored-By: Claude (glm-5) <noreply@anthropic.com>

db/materials_to_delete.py

@@ -3,7 +3,7 @@
 从数据库查询指定负责人需要删除的物料编码
 """
 
-from typing import List, Dict, Any
+from typing import List, Dict, Any, Optional
 from db.connection import get_connection
 
 
@@ -49,6 +49,46 @@ def get_all_materials_to_delete() -> List[Dict[str, Any]]:
         return results
 
 
+def get_materials_to_delete_by_managers(
+    manager_names: Optional[List[str]] = None,
+) -> List[str]:
+    """
+    根据负责人列表查询待删除物料编码
+
+    Args:
+        manager_names: 负责人姓名列表
+            - None 或空列表：返回所有物料编码
+            - 有值：返回指定负责人的物料编码
+
+    Returns:
+        物料编码列表
+    """
+    if not manager_names:
+        # 查询所有物料编码
+        query = """
+            SELECT [MaterialCode]
+            FROM [dbo].[MaterialsToBeDeleted]
+            WHERE [MaterialCode] IS NOT NULL
+        """
+        with get_connection() as conn:
+            results = conn.execute_query(query)
+            material_codes = [row["MaterialCode"] for row in results if row["MaterialCode"]]
+            return material_codes
+    else:
+        # 使用 IN 子句查询多个负责人
+        placeholders = ", ".join(["?"] * len(manager_names))
+        query = f"""
+            SELECT [MaterialCode]
+            FROM [dbo].[MaterialsToBeDeleted]
+            WHERE [MaterialCode] IS NOT NULL
+              AND [ManagerName] IN ({placeholders})
+        """
+        with get_connection() as conn:
+            results = conn.execute_query(query, tuple(manager_names))
+            material_codes = [row["MaterialCode"] for row in results if row["MaterialCode"]]
+            return material_codes
+
+
 def should_delete_material(manager_name: str, material_code: str) -> bool:
     """
     检查指定物料编码是否需要删除