refactor: use VBA-Excel/VBA-Access as default output dirs by file type

Co-Authored-By: Claude Opus 4.6 <noreply@anthropic.com>

extract_vba.py

@@ -76,8 +76,10 @@ class VBAExtractor:
         elif VBA_OUTPUT_DIR is not None:
             self.output_dir = Path(VBA_OUTPUT_DIR)
         else:
-            # 使用目标文件同目录下的VBA文件夹
-            self.output_dir = self.source_path.parent / "VBA"
+            # 根据文件类型使用不同的默认文件夹
+            file_type = get_file_type(self.source_path)
+            default_dir = "VBA-Access" if file_type == 'access' else "VBA-Excel"
+            self.output_dir = self.source_path.parent / default_dir
 
         # 创建输出目录结构
         self.modules_dir = self.output_dir / STANDARD_MODULE_DIR

import_vba.py

@@ -472,8 +472,9 @@ def main():
         if not vba_path.is_absolute():
             vba_path = script_dir / vba_path
     else:
-        # 使用目标文件同目录下的 VBA 文件夹
-        vba_path = target_path.parent / "VBA"
+        # 根据文件类型使用不同的默认文件夹
+        default_dir = "VBA-Access" if file_type == "access" else "VBA-Excel"
+        vba_path = target_path.parent / default_dir
 
     if not vba_path.exists():
         print(f"错误: VBA 代码目录不存在: {vba_path}")