refactor: use VBA-Excel/VBA-Access as default output dirs by file type
Co-Authored-By: Claude Opus 4.6 <noreply@anthropic.com>
This commit is contained in:
@@ -76,8 +76,10 @@ class VBAExtractor:
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elif VBA_OUTPUT_DIR is not None:
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elif VBA_OUTPUT_DIR is not None:
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self.output_dir = Path(VBA_OUTPUT_DIR)
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self.output_dir = Path(VBA_OUTPUT_DIR)
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else:
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else:
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# 使用目标文件同目录下的VBA文件夹
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# 根据文件类型使用不同的默认文件夹
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self.output_dir = self.source_path.parent / "VBA"
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file_type = get_file_type(self.source_path)
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default_dir = "VBA-Access" if file_type == 'access' else "VBA-Excel"
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self.output_dir = self.source_path.parent / default_dir
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# 创建输出目录结构
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# 创建输出目录结构
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self.modules_dir = self.output_dir / STANDARD_MODULE_DIR
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self.modules_dir = self.output_dir / STANDARD_MODULE_DIR
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@@ -472,8 +472,9 @@ def main():
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if not vba_path.is_absolute():
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if not vba_path.is_absolute():
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vba_path = script_dir / vba_path
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vba_path = script_dir / vba_path
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else:
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else:
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# 使用目标文件同目录下的 VBA 文件夹
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# 根据文件类型使用不同的默认文件夹
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vba_path = target_path.parent / "VBA"
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default_dir = "VBA-Access" if file_type == "access" else "VBA-Excel"
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vba_path = target_path.parent / default_dir
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if not vba_path.exists():
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if not vba_path.exists():
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print(f"错误: VBA 代码目录不存在: {vba_path}")
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print(f"错误: VBA 代码目录不存在: {vba_path}")
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